Here is the construction of a proof that all triangles are isosceles:
- Draw a line bisecting the angle A.
- Draw a line bisecting the segment BC that is perpendicular to BC.
- If these two lines are parallel, then we know that we have an isosceles triangle. Assume now that they are not parallel. Then they must intersect at a point P.
- We may now draw lines from P to E and F that are perpendicular to AB and AC, respectively.
- The two triangles alpha are equal since they have equal angles share one side.
- Thus, PE = PF.
- Since DP is perpendicular to BC,the two triangles gamma must be right triangles.
- Since DP bisects BC, D is the midpoint of BC. Thus, the two triangles gamma share two sides and one angle and are therefore equal triangles.
- Thus, PB = PC.
- With two equal sides (PB = PC and PF = PE) and an equal angle each, the two triangles beta must therefore be equal triangles.
- Hence, BE + EA = CF + FA and the triangle must be isosceles, q.e.d.
Obviously something is amiss here. Can you figure it out?
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